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E0070 in Rust: Invalid left-hand side expression for an assignment

Last updated: January 06, 2025

Understanding Rust's E0070: Invalid left-hand side expression for an assignment

When programming in Rust, you might encounter various compile-time errors which are informative yet can sometimes seem cryptic at first glance. One such error is the E0070 error, which indicates an 'Invalid left-hand side expression for an assignment.' In this article, we will delve into the details of this error, understand why it occurs, and learn how to fix it.

Understanding the Assignment in Rust

In Rust, variables can be assigned using the '=' operator. The value on the right-hand side (RHS) is evaluated and assigned to the variable or expression on the left-hand side (LHS). In simple terms, the LHS defines where the result of the RHS evaluation will be stored.

An assignment statement can look like this:

let mut x = 10; // define a mutable variable
x = 20; // valid assignment

In Rust, for an assignment to take place, the LHS of the assignment must be something that can store a value, essentially a mutable variable.

The E0070 Error: What Does It Mean?

The E0070 error occurs when there is an attempt to assign a value to an expression that cannot be legally assigned to.

fn main() {
    let y = 5;
    1 + 2 = y; // This will produce E0070 error
}

In this example, 1 + 2 is an expression that evaluates to a value but cannot store a value. Therefore, you cannot have 1 + 2 on the LHS of an assignment because it's not a valid storage location.

Mutable Variables and Patterns

Rust ensures memory safety and logical correctness at compile-time, so operations that don't make sense, such as declaring immutable pieces on the LHS, are disallowed. Consider the following example:

fn main() {
    let mut a = (1, 2);
    a.0 = 5; // This is valid because a is mutable, i.e., allowed to be changed

    let b = (1, 2);
    b.0 = 5; // This line will cause an E0070 error because b is immutable
}

In this code snippet, the tuple b is immutable, and consequently trying to assign a new value to b.0 results in an E0070 error.

How to Fix the E0070 Error

The solution to fixing E0070 errors depends on ensuring that the LHS of an assignment is mutable. You can generally take two main approaches:

  • If the variable is meant to be mutable, you need to declare it with the mut keyword.
  • Ensure that the LHS is actually a valid target for the assignment, not a temporary result of an arithmetic operation or another read-only expression.

Let's correct the previous example:

fn main() {
    let mut b = (1, 2);
    b.0 = 5; // Now valid since b is mutable
}

Always ensure the LHS target is capable of storing the newly assigned value. Scrutinize expressions or nested patterns to ascertain if they genuinely represent storage locations in memory.

Conclusion

Rust’s error messages are targeted at helping developers maintain safe and logical code. The E0070 error may seem limiting at first but underscores the importance Rust places on safe concurrency and memory usage. By ensuring LHS expressions can legally and logically store values, you can overcome this issue and write more robust Rust programs.

With practice, managing such errors will soon become intuitive, enhancing your skills as a Rust developer.

Next Article: E0071 in Rust: Expected `struct`, `enum`, or `union` but found something else

Previous Article: E0063 in Rust: Missing fields in struct initializer

Series: Common Errors in Rust and How to Fix Them

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