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E0133 in Rust: Dereference of raw pointer in constant expression is not allowed

Last updated: January 06, 2025

In Rust programming, you may encounter the compiler error E0133 if you attempt to dereference a raw pointer in a constant expression. Rust's emphasis on safety means that certain operations which involve dereferencing raw pointers are restricted, particularly when done in a context where the compiler cannot guarantee memory safety, like in a constant expression.

Understanding Raw Pointers in Rust

Raw pointers in Rust can be either mutable (*mut T) or immutable (*const T). These pointers are distinct from references because they aren’t guaranteed to be pointing to a valid object, and unlike references, they do not enforce borrowing rules. They are useful for interfacing with C code or performing low-level memory manipulation, but they must be used with caution.

Constant Expressions in Rust

Constant expressions are evaluated at compile time and must not include any operation that might produce different results each time they're evaluated. Hence, compile time logical errors like dereferencing the raw pointers often trigger errors.

Why Dereferencing in Constants Is Disallowed

The Rust compiler disallows dereferencing raw pointers within constant expressions as they could introduce undefined behavior. In constant contexts, safety guarantees and immutability are primary; dereferencing raw pointers violates these guarantees because it may attempt to access invalid addresses.

Example of E0133 Error

const NUM_PTR: *const i32 = &42 as *const i32;
// Attempting to dereference at compile time
const DEREF: i32 = unsafe { *NUM_PTR }; // This will trigger E0133

The above code attempts to dereference a raw pointer within a constant declaration, resulting in the error.

Solutions and Alternatives

If you encounter E0133, consider the following solutions:

  1. Use runtime operations: Move the pointer dereferencing to a function where safety can be checked at runtime.
fn main() {
    let num: i32 = 42;
    let num_ptr: *const i32 = #
    let deref: i32 = unsafe { *num_ptr };
    println!("Dereferenced value: {}", deref);
}

In this case, the dereferencing is conducted inside the main function, under an unsafe block, avoiding the compile-time restriction.

  1. Use arrays or slices: Wrap the values within arrays or slices to evaluate constants, if applicable, while ensuring indirection happens in runtime.

Understanding Unsafe in Rust

It's crucial to grasp the concept of unsafe in Rust. When a block of code is marked unsafe, it is signaling that the constraints typically enforced by Rust can be manually supervised by you, the developer. However, it's generally advised to keep unsafe code to the absolute minimum necessary.

Using unsafe implies a promise that the code within the block satisfies Rust's safety guarantees under all possible execution conditions. As you work with features like raw pointers, always remember their place in Rust: powerful when necessary, but risky without careful handling.

Conclusion

In Rust, encountering E0133 is a common hurdle for developers who are transitioning from more lenient environments. Awareness of when and how to leverage pointers safely, particularly raw pointers, can help mitigate such errors. Beginning with an understanding of why these operations are disallowed in constants and moving towards actionable alternatives can empower you to adopt safer practices without compromising the power and flexibility Rust aims to offer developers.

Next Article: E0137 in Rust: Multiple `main` functions found in the same crate

Previous Article: E0132 in Rust: Partial initializations of uninitialized structures are not allowed

Series: Common Errors in Rust and How to Fix Them

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